c语言,求今年第几天?答:31,28,31,30,31,30,31,31,30,31,30,31};scanf("%d-%d-%d",&year,&month,&day);if((year%4==0&&year%100)||year%400==0) a[2]=29;for(i=0;i<month;i++)d+=a[i];d+=day;printf("%d年的第%d天",
用c语言编写一程序,用户输入日期,计算该日是今年的第几天答:include"stdio.h"include"stdlib.h"intmain(){ intday,month,year,sum,leap;printf("\npleaseinputyear,month,day\n");scanf("%d,%d,%d",&year,&month,&day);switch(month)/*先计算某月以前月份的总天数*/ { case1:sum=0;break;case2:sum=31;break;case3:sum=59;break;case4:sum=90...
用C语言计算一下今天是今年的第几天!!求解答:29,31,30,31,30,31,31,30,31,30,31}}; printf("请输入当天的日期:"); scanf("%d %d %d",&year,&month,&day); if((year % 4 == 0 && year % 100 != 0) || year % 400 == 0) { for(i=0;i<month-1;i++) { days += date[1][i]...
C语言中输入一个日期计算他是今年的第几天答:3、累加之前各月天数;4、累加当前日值;5、输出结果。二、注意点:可以使用数组存储各个月份的天数,用循环累加。需要注意的是闰年的判断。对于闰年,2月要多加一天。三、参考代码:include <stdio.h>int main(){ int mdays[12] = {31,28,31,30,31,30,31,31,30,31,30,31};//十二个...
输入某年某月某日,输出这是今年的第几天,C语言问题答:3、累加之前各月天数;4、累加当前日值;5、输出结果。二、注意点:可以使用数组存储各个月份的天数,用循环累加。需要注意的是闰年的判断。对于闰年,2月要多加一天。三、参考代码:include <stdio.h>int main(){ int mdays[12] = {31,28,31,30,31,30,31,31,30,31,30,31};//十二个...