模糊矩阵最大最小合成法答:n=size(b,2);for i=1:m for j=1:n ab(i,j)=max(min([a(i,:);b(:,j)']));end 再键入 a=[0.4,0.5,0.6;0.1,0.2,0.3],b=[0.1,0.2;0.3,0.4;0.5,0.6]ab=synt(a,b),ba=synt(b,a)计算得 a = 0.4000 0.5000 0.6000 0.1000 0.2000 ...
模糊矩阵最大最小合成法答:n=size(b,2);for i=1:m for j=1:n ab(i,j)=max(min([a(i,:);b(:,j)']));end 再键入 a=[0.4,0.5,0.6;0.1,0.2,0.3],b=[0.1,0.2;0.3,0.4;0.5,0.6]ab=synt(a,b),ba=synt(b,a)计算得 a = 0.4000 0.5000 0.6000 0.1000 0.2000 ...