将一个数组中的值按逆序重新存放。例如,原来顺序为8,6,5,4,1。要求...答:include<stdio.h> int main(){ char arr[10] = { 1, 2, 3, 4, 5, 6, 7, 8, 9, 0 };int i = 0;int len = sizeof(arr) / sizeof(arr[0]);int tmp = 0;for (i = 0; i < (len/2); ++i) //进行len/2次交换 { tmp = arr[9 - i];arr[9 - i] = arr...
将一个数组中的值按逆序重新存放.例如,原来的顺序为8,6,5,4,1.要求...答:int a[20]={1,0},i,n,j;printf("请输入数组元素的个数:");scanf("%d",&n);printf("请输入数组元素:\n");for(i=0;i<n;i++)scanf("%d",&a);for(i=0;i<n/2;i++)a=a[n-1-i];printf("逆序存放后的数组:\n");for(i=0;i<n;i++)printf("%d",a);return 0;} ...