用高斯完全主元素消去法求解方程组答:4 11 -1 33 6 3 12 36 r3/3,r1-2r2,r2-2r3 ~0 -25 4 -46 0 9 -9 9 2 1 4 12 r2/9,r1+25r2,r3-r2,交换r1r3 ~2 0 5 11 0 1 -1 1 0 0 -21 -21 r3/-21,r1-5r3,r2+r3,r1/2 ~1 0 0 3 0 1 0 2 0 0 1 1 于是解得x1=3,x2=2,x3=1 ...
c语言 列主元素消去法求方程组答:3 void main()4 { 5 float a[4][4] = { {0, 0, 0, 0}, {0, 1, 2, 3}, {0, 2, 1, 3}, {0, 3, 2, 1} }, b[4] = 6 { 7 0, 8, 22, 28}, d, t, sum = 0;8 int i, j, k, l;9 for (k = 1; k <= 2; k++)10 { 11...